Question

X square - 10 X - 39 factorise ​

Answer 1

Given :

• $x^2-10x-39$

To Do :

• Factorise the equation.

Solution :

$\implies x^2 -10x-39$

$\implies x^2 +3x -13x- 39$

$\implies x(x+3)-13(x+3)$

$\implies (x-13)(x+3)$

Required Answer :

$(x-13)(x+3)\text{are the factors of the given polynomial}$

Answer 2

Question

X square - 10 X - 39 factorise

x² - 10x -39. Factorise

Answer

${ \boxed{ \color{navy}{ \tt {x {}^{2} - 10x - 39}}}}$

${ \color{navy}{ \tt \leadsto{x {}^{2} - (3 - 13)x - 39}}}$

${ \color{navy}{ \tt \leadsto{x {}^{2} - 3 x + 13x - 39}}}$

${ \color{navy}{ \tt \leadsto{x(x - 3)- 13(x - 3) }}}$

${ \color{navy}{ \tt \leadsto{(x - 13)(x - 3) }}}$

Hence, ${ \color{navy}{ \tt {(x - 13)(x - 3) }}}$ are the required answer.