Question

X square + 11 x + 28​

Answer 1

Answer:

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Answer 2

Take the factors are 7 and 4

Then ,

X^2+7X+4X+28 =0

take x common in first two then 4 as common for next two

Which leaves us to

X[X+7]+4[X+7] =0

So which means

X+7=0 and x+4=0

So after transposing the constant to the other side we got

x =-7 or X=-4

Hope you understood