Question

X square + 17 X + 33/4= 0 solve by completing square method

Answer 1

Answer:

${x}^{2} + 17x = - \frac{33}{4} \\ adding \: {( \frac{17}{2}) }^{2} \: on \: both \: sides \\ {x}^{2} + 17x + {( \frac{17}{2}) }^{2} = {( \frac{17}{2}) }^{2} - \frac{33}{4} \\ {(x + \frac{17}{2} )}^{2} = \frac{289}{4} - \frac{33}{4} \\ {(x + \frac{17}{2}) }^{2} = \frac{256}{4} \\ {(x + \frac{17}{2}) }^{2} = 64 \\ {(x + \frac{17}{2}) }^{2} = {8}^{2} \\ x + \frac{17}{2} = 8 \: or \: x + \frac{17}{2} = - 8 \\ x = - \frac{1}{2} \: or \: - \frac{33}{2}$

Answer 2

Answer:

above answer is correct