x square + 2 kx + 4 equals to zero has a root 2 then find the value of k
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given equation is
x^2+2kx+4=0
put x= 2
(2)^2+2k(2)+4=0
4+4k+4=0
4k+8=0
4k= -8
k=-8/4 =-2
k=-2
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Here's your answer, dear friend ...
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