Question

X square + 2 root 2 x minus 6

Answer 1

a=1 , b = 2√2, c= -6
p(x)=-( 2√2) +-√2√2square-4*1*-6/2*1

p(x)= 2√2±√8+24/2

p(x)= 2√2+-√32/2

(+) sign lene pr
2√2 +√32/2= 4√2+√32/2

(-) sign lene pr
4√2 -√32/2

Formula which i use = -b ±√b square - 4×a×c /2a

Answer 2

Answer:

The general solution of a quadratic equation is ax² + bx + c.

The sum of the root of a quadratic equation is equal to - $\frac{b}{a}$, and the product of the roots is equal to $\frac{c}{a}$.

Step-by-step explanation:

x² + 2√2x - 6

The general solution of a quadratic equation is:

ax² + bx + c.

a = coefficient of x²

b = coefficient of x

c = constant term

The root of the given polynomial using the quadratic formulae:

x = $\frac{-b +-\sqrt{b^{2} - 4ac}}{2a}$

x = [-2√2   ±  √[(2√2)² - (4 . 1 . -6)]] /2

=> x = - √2 + 2√2 ,  - √2 - 2√2

=> x = √2 , -3√2

Now, if we add the zeros

√2 +  -3√2

= - 2√2    = - $\frac{b}{a}$

If we multiply the zeros

√2  * ( -3√2)

= - 6

= - 6    =  $\frac{c}{a}$

Therefore, we can conclude that the sum of the root of a quadratic equation is equal to - $\frac{b}{a}$, and the product of the roots is equal to $\frac{c}{a}$ .

Where, a = coefficient of x²

b = coefficient of x

c = constant term