Question

X square + 2 root 2x minus 6

Answer 1

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Answer 2

Hey !!!! ^_^

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${x}^{2} + 2 \sqrt{2x} - 6 = 0 \\ \\ \\ {x}^{2} + 3 \sqrt{2}x - \sqrt{2x} - 6 = 0\\ \\ x(x + 3 \sqrt{2}) - \sqrt{2} (x + 3 \sqrt{2} ) = 0 \\ \\ (x + 3 \sqrt{2}) (x - \sqrt{2} ) = 0 \\ \\ x = - 3 \sqrt{2} \: \: .....or .....\:x = \sqrt{2}$
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