Question

X square + 2 under root 2 x minus 6​

Answer 1

Hey

$x {}^{2} + 2 \sqrt{2} x - 6 = 0 \\ \\ = > x {}^{2} + 3 \sqrt{2} x - \sqrt{2} x - 6 = 0 \\ \\ = > x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) = 0 \\ \\ = > (x - \sqrt{2} )(x + 3 \sqrt{2} ) = 0 \\ \\ = > x = \sqrt{2} \: or \: - 3 \sqrt{2}$

I hope it helps you!!!

Answer 2

Answer:

Here is your answer