X square + 2 X + 1 equal to zero
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x2 +2x+1=0 x2+x+x+1=0 x(x+1)+1(x+1)=0
(x+1) (x+1) =0 x= -1 or x=-1 equal and distinct
(x+1) (x+1) =0 x= -1 or x=-1 equal and distinct
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Hey mate here is your answer
x^2 + 2x + 1 = 0
=> x^2 + x + x + 1 = 0
=> x (x+1) + 1 (x+1) = 0
=> (x+1) (x+1) =0
=> (x+1)^2 = 0
Hope this will help you dear ⤴
Thanks
x^2 + 2x + 1 = 0
=> x^2 + x + x + 1 = 0
=> x (x+1) + 1 (x+1) = 0
=> (x+1) (x+1) =0
=> (x+1)^2 = 0
Hope this will help you dear ⤴
Thanks
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