Question

x square - 2 x minus 8 find zeroes of quadratic polynomial and verify the relationship between the zeroes and the coefficient?​

Answer 1

a=1;b=-2; c=-8

Step-by-step explanation:

x^2-2x-8

=x^2-4x+2x-8=0

=x(x-4)+2(x-4)=0

=x-4=0 ;x+2=0

=x=4 ;x=-2

sum of zeroes=-b/a=-(-2)/1=2

product of zeroes=c/a=-8/1=-8

hope it may help u guys