X square + 23 x + 130 factorise
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Given f(x) = x² + 23x + 130,
For Finding Factors , First Of All Equate The Expression to 0,
=> f(x) = x² + 23x + 130 = 0
Now By Splitting The Middle Term Method,
=> Sum = 23 , Product = 130, So the Values are = 13 and 10,
=> Now , Replace 23x with 10x and 13x,
f(x) = x² + 10x + 13x + 130 = 0
=> Taking x and 13 as Common,
f(x) = x ( x + 10 ) + 13 ( x + 10 ) = 0
=> Now take (x + 13)as common
f(x) = (x+13) × (x+10)
=> The. Factors are {(x+10) and (x+13)}
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