x square+2kx+4 =0 has a root x=2 find the value of k
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Answer:
p(X)=x^2+2kx+4=0
put X=2
p(2)=(2^2)+2(k)(2)+4=0
=4+4k+4=0
=8+4k=0
=4k=-8
=k=-8/4
=k=-2
hence the value of k is -2
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