x square -2x = (-2) (3-x) check this is quadratic eqation or not and solve it
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Answered by
0
x^2 - 2x = (-2)(3-x)
x^2 - 2x = -6 +2x
x^2 -4x + 6 =0
surely this is an quadratic equation because the degree of this polynomial is 2
hope it helps.
and since b^2 - 4ac < 0 so it doesn't have real roots.
x^2 - 2x = -6 +2x
x^2 -4x + 6 =0
surely this is an quadratic equation because the degree of this polynomial is 2
hope it helps.
and since b^2 - 4ac < 0 so it doesn't have real roots.
Muskan74600:
wait......
how
??
the highest power of x is 2 and coefficient of that term is not 0 so that gives the degree 2
Answered by
1
Hey
Here is your answer,
X^2-2x = (-2) (3-x)
X^2 -2x = -6 +2x
X^2 -2x -2x +6=0
X^2 -4x +6=0
Hey, it is a quadratic equation.....
B^2 -4ac = (-4)^2 -4x 1x6
16-24=0
-8 is not equal to 0.
Therefore the equation has distinct real roots.
Hope it helps you!
Here is your answer,
X^2-2x = (-2) (3-x)
X^2 -2x = -6 +2x
X^2 -2x -2x +6=0
X^2 -4x +6=0
Hey, it is a quadratic equation.....
B^2 -4ac = (-4)^2 -4x 1x6
16-24=0
-8 is not equal to 0.
Therefore the equation has distinct real roots.
Hope it helps you!
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