Question

x square-2x-8 Find the zeros
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Answer 1

Answer:

$x {}^{2} - 2x - 8 \\ x {}^{2} - 4x + 2x - 8 \\ x(x - 4) + 2(x - 4) \\ (x - 4)(x + 2)$

so zeroes are

4 and -2