X square + 3 root 2 x minus 6
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x^2 + 3√2 x - 6 = 0
this is a quadratic equation,
let, a = 1 , b = 3 √2 , c = - 6
let first find ,
discriminant (D) = b^2 - 4ac = (3√2)^2 - 4(1)(-6)
D = 18+ 24 = 42
D = 42
now for "x"
x = - b +- √D / 2
x = - 3√2 +- √42 / 2(1)
x = - 3√2 + √42 / 2 , -3√2 - √42 / 2
x = -(3√2 -√42) / 2 , - (3√2 + √42 ) / 2 = 0
{(2x + 3√2 )- √42 } , { (2x +3√2) + √42 }
hence,
x^2 + 3√2 x - 6= { (2x + 3√2 ) -√42 ) } { (2x + 3√2 ) +√42 ) }
are the factors of given quadratic polynomial.
●hope it helps●
this is a quadratic equation,
let, a = 1 , b = 3 √2 , c = - 6
let first find ,
discriminant (D) = b^2 - 4ac = (3√2)^2 - 4(1)(-6)
D = 18+ 24 = 42
D = 42
now for "x"
x = - b +- √D / 2
x = - 3√2 +- √42 / 2(1)
x = - 3√2 + √42 / 2 , -3√2 - √42 / 2
x = -(3√2 -√42) / 2 , - (3√2 + √42 ) / 2 = 0
{(2x + 3√2 )- √42 } , { (2x +3√2) + √42 }
hence,
x^2 + 3√2 x - 6= { (2x + 3√2 ) -√42 ) } { (2x + 3√2 ) +√42 ) }
are the factors of given quadratic polynomial.
●hope it helps●
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