x square + 3 x + 1 =0
what is x
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✖ = -2
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Answer: x2−3x+1=0
Considering the coefficients and constants in the equation
a=1 [Coefficient of x2]
b= -3 [Coefficient of x]
c = 1 [The constant term]
The formula for the discriminant of a quadratic equation is
D=b2−4ac
Substituting values for a, b and c
D=(−3)2−4∗1∗1
D=9−4
D=5
Now, the formula for finding 'x' using the discriminant is
x = (−b±√D)/2a
Substituting values for b, D and a in the above formula, you get
x = (3±√5)/2
Hence, the values for 'x' are
x = (3+√5)/2 and (3−√5)/2
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