x square + 3 x +8 =0 find discriminant
Austin222:
D is less than zero
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Answer :
x² + 3x + 8 = 0
On comparing it with the standard form of quadratic equation ax² + bx + c = 0, we get -
a = 1, b = 3, c = 8
Discriminant = b² - 4ac
⇒ D = (3)² - 4 * 1 * 8
⇒ D = 9 - 32
⇒ D = -23
∴ D < 0
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Given =>
A = 1
B = 3
C = 8
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D = B² - 4AC
D = 3² - 4 × 1 × 8
D = 9 - 32
D = - 23
D < 0
Hence , quadratic equation has No real roots
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