Question

x square - 30xy + 29y square factorise

Answer 1

Answer:

( x - 29y )( x - y )

Step-by-step explanation:

Given polynomial : x^2 - 30xy + 29y^2

Factorization by splitting its middle term : -

= > x^2 - 30xy + 29y^2

Spitting the middle term of the polynomial ( that is 30, numeric co efficient ) in two number such that their product becomes equal to the product of the numeric co efficient of other term( that are 1 { with x^2 } and 29{ with xy }.

So,

30 = 29 + 1, as the product of 29 and 1 is equal to the product of numeric co efficient of other terms,

= > x^2 - 30xy + 29y^2

= > x^2 - ( 29 + 1 )xy + 29y^2

= > x^2 - 29xy - xy + 29y^2

= > x( x - 29y ) - y( x - 29y )

= > ( x - 29y )( x - y )

Hence,

x^2 - 30xy + 29y in factorized ( or product ) from is ( x - 29y )( x - y ) .

Answer 2

QUESTION :

x square - 30xy + 29y square factorise

ANSWER :

we have to factories

the quadratic polynomial

x²-30xy+29y²

so this question can be solved by splitting the middle term method

for that we required the two no. such that there

sum = -30

product = 29

so the two no. are

-29 and -1

as there

product =( -29)(-1)= 29

and

sum = -29+(-1) =-29-1 =-30

so by applying using the splitting the middle term method

we get

x²-30xy+29y²

= x²-29xy-xy+29y²

by taking X in common by first two terms and y in common by last two terms

we get

x²-29xy-xy+29y²

= x(x-29y)-y(x-29y)

now by taking (x-29y) in common we have

x(x-29y)-y(x-29y)

= (x-29y)(x-y)

hence

x²-30xy+29y² = (x-29y)(x-y)

hence the factors of

x²-30xy+29y

are

(x-29y) and (x-y)