Question

X square + 4 x + 4 is equal to 2 discriminant of quadratic equation​

Answer 1

Answer:

$8$

Step-by-step explanation:

${x}^{2} + 4x + 4 = 2$

${x}^{2} + 4x + 2 = 0$

$discriminant = {b}^{2} - 4ac$

${4}^{2} - 4(1)(2)$

$16 - 8$

$8$

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Answer 2

$Given \: Quadratic \: Equation : \\x^{2} + 4x + 4 = 2$

$\implies x^{2} + 4x + 4 - 2 = 0$

$\implies x^{2} + 4x + 2= 0$

/* Compare this equation with ax²+bx+c=0, we get */

$a = 1 , b = 4 \:and \:c = 2$

$\red{ Discreminant (D) } = b^{2} - 4ac \\= 4^{2} - 4 \times 1 \times 2 \\= 16 - 8 \\= 8 > 0$

$D> 0$

$\blue {( Roots \: are \: real \: and \: distinct .) }$

Therefore.,

$\red{ Discreminant (D) } \green {= 8 }$

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