X square + 4 y square equal to 4 x y then x is 2 y is
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Answered by
1
Solve by substitution x^2 + y^2 = 8 and x - y = 4
The equations x^2 + y^2 = 8 and x - y = 4 have to be solved by substitution.
x - y = 4
=> x = 4 + y
Substitute in x^2 + y^2 = 8
=> (4 + y)^2 + y^2 = 8
=> 16 + y^2 + 8y + y^2 = 8
=> y^2 + 4y + 4 = 0
=> (y + 2)^2 = 0
=> y = -2
x = 4 + y = 2
Answered by
1
Answer:
x² + 4y² = 4xy
x² + (2y)² - 4xy = 0
x² + (2y)² - 2(x)(2y) = 0
As ( a - b )² = a² + b² - 2ab
=> ( x - 2y )² = 0
Taking square roots on both sides
=> x - 2y = 0
=> x = 2y
Best of Luck !!!!
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