Question

x square+4x-5 equation
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Answer 1

$Given \: x^{2} + 4x - 5 = 0$

$\implies x^{2} + 5x - 1x - 5 = 0$

$\implies x( x + 5 ) - 1(x+5) = 0$

$\implies (x+5)(x-1) = 0$

$\implies x + 5 = 0 \: Or \: x - 1 = 0$

$\implies x = -5 \: Or \: x = 1$

Therefore.,

$\green { x = -5 \: Or \: x = 1}$

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Answer 2

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