Question

X square+ 4x+5 ( in nature of the roots of the quadratic equation) explain it in step by step process

Answer 1

Answer:

x²+4x+5

using b²-4ac

=16-4(1)(5)

=16-20

=-4

since b²-4ac < 0 therefore the roots are non real and not equal

Answer 2

${x}^{2} + 4x + 5 \\ {b}^{2} - 4ac = 16 - 20 = - 4$

Since the determinant is negative

(ie, b²-4ac<0) , the equation will have non real and imaginary roots

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