Question

X square - 4x-96. Solve the quadratic equation

Answer 1

$\huge \rm {x}^{2} - 4x - 96 \\ \\ \leadsto \: \: \: \: \: \: \: \: \: \bf {x}^{2} - 12x + 8x - 96 = 0 \\ \leadsto \: \: \: \: \bf x(x - 12) + 8(x - 12) = 0 \\ \leadsto \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bf (x - 12)(x + 8) = 0 \\ \\ \leadsto \: \: \: \: \sf \: \: \: \: \: x = \: \red{12 }\: \: \: \: or \: \: \: ( \red{- 8})$