Math, asked by ravi1014, 1 year ago

x square+4y square+4yx-64 factorise

Answers

Answered by 22072003
9
x² + 4y² + 4yx - 64

= ( x )² + ( 2y )² + 4xy - 64

= [ ( x )² + ( 2y )² + 2 ( x ) ( 2y ) ] - 64

<b>a² + b² + 2ab = ( a + b )²</b>

= ( x + 2y )² - 64

= ( x + 2y )² - ( 8 )²

<b>a² - b² = ( a + b ) ( a - b )</b>

= ( x + 2y + 8 ) ( x + 2y - 8 )
Answered by brunoconti
1

Answer:


Step-by-step explanation:


x^2 + 4y^2 + 4xy - 64 =


= (x + 2y)^2 - 8^2 =


= (x + 2y -8)(x + 2y + 8)

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