Question

x square+4y square+4yx-64 factorise

Answer 1

x² + 4y² + 4yx - 64

= ( x )² + ( 2y )² + 4xy - 64

= [ ( x )² + ( 2y )² + 2 ( x ) ( 2y ) ] - 64

$<b>a² + b² + 2ab = ( a + b )²</b>$

= ( x + 2y )² - 64

= ( x + 2y )² - ( 8 )²

$<b>a² - b² = ( a + b ) ( a - b )</b>$

= ( x + 2y + 8 ) ( x + 2y - 8 )

Answer 2

Answer:

Step-by-step explanation:

x^2 + 4y^2 + 4xy - 64 =

= (x + 2y)^2 - 8^2 =

= (x + 2y -8)(x + 2y + 8)