Question

X square + 5 x + 3 is equals to zero solve quadratic solve the factors​

Answer 1

and. is given in the photo

I HOPE U WILL UNDERSTAND

Answer 2

$\red{\huge{\underline{\overline{\mid{\bold{\purple{\: \: SOLUTION \: \: \red{\mid}}}}}}}}$

$\underline{ \bold{ \: \: TO \: \: SOLVE \: \: : }} \to \: \: \: \: \: \bold{x {}^{2} + 5x + 3 = 0 }$

$\star \: \: \underline{ \bold{ \: \: We \: \: know \: \: that \: \: }} \to \\ \\ \\ \bold{A \: \: quadratic \: \: equation \: \: is \: \: in \: \: the \: \: form} \\ \bold{of \: \: ax {}^{2} + bx + c = 0 \: \: and \: \: the \: \: value \: \: of \: \: x \: : } \\ \\ \boxed{\bold{x = \frac{ - b \: \pm \: \sqrt{b {}^{2} - 4ac \: \: } }{2a}} }$

$\bold{In \: \: the \: \: equation \: \: x {}^{2} + 5x + 3 = 0 } \\ \\ \underline{\bold{ \: \: Suppose ,\: \: }} \\ \\ \bold{a = 1 \: \: \: \: b = 5 \: \: \: \: and \: \: \: \: c = 3}$

$\bold{Hence, \: \: } \\ \\ \bold{x = \frac{ \: - b \: \pm \: \sqrt{b {}^{2} - 4ac \: \:} \: \: \: }{2a} } \\ \\ \bold{ = \frac{ \: - 5 \: \pm \: \sqrt{(5) {}^{2} - 4 \times 1 \times 3 \: \: } \: }{2 \times 1} } \\ \\ \bold{ = \frac{ - 5 \: \pm \: \sqrt{25 - 12} }{2} } \\ \\ \bold{ = \frac{ - 5 \: \pm \: \sqrt{13} }{2} }$

$\bold{Therefore, \: \: } \\ \\ \bold{x = \frac{ - 5 + \sqrt{13} }{2 } \: \: \: \: \: Or, \: \: \: \: \: \: \frac{x = - 5 - \sqrt{13} }{2} }$