x square - 5 x minus 36 how to solve
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Answered by
4
x^2-2(5/2)x-36
=x^2-2(5/2)x+25/4-25/4-36
=(x-5/2)^2-25/4-144/4
=(x-5/2)^2-(25+144)/4
=(x-5/2)^2-169/4
=x^2-2(5/2)x+25/4-25/4-36
=(x-5/2)^2-25/4-144/4
=(x-5/2)^2-(25+144)/4
=(x-5/2)^2-169/4
Answered by
5
Hey !!!
x² - 5x - 36
x² - 9x + 4x - 36
x ( x - 9 ) - 4 ( x - 9 )
( x - 4 ) ( x - 9 ) is factor of this polynomial
And zeroes of this polynomial is
(x - 4 ) ( x - 9 ) = 0
x - 4 = 0
x = 4
.
similarly , x - 9 = 0
x = 9
hence, 4 and 9 is the zero of this given quadratic polynomial
_________________________
Hope it helps you !!;
@Rajukumar111
x² - 5x - 36
x² - 9x + 4x - 36
x ( x - 9 ) - 4 ( x - 9 )
( x - 4 ) ( x - 9 ) is factor of this polynomial
And zeroes of this polynomial is
(x - 4 ) ( x - 9 ) = 0
x - 4 = 0
x = 4
.
similarly , x - 9 = 0
x = 9
hence, 4 and 9 is the zero of this given quadratic polynomial
_________________________
Hope it helps you !!;
@Rajukumar111
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