x square + 5x - (a square+ a-6) =0
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Answer:
x = a-3 or x = -(a+2)
Explanation:
a²+a-6
= a²-3a+2a-6
= a(a-3)+2(a-3)
= (a-3)(a+2)---(1)
Now ,
x²+5x-(a-3)(a+2)=0
Splitting the middle term , we
get
=> x²-(a-3)x+(a+2)x-(a-3)(a+2)=0
=> x[x-(a-3)]+(a+2)[x-(a-3)]=0
=> [x-(a-3)][x+(a+2)]=0
=> x-(a-3)=0 or x+(a+2)=0
=> x = a-3 or x = -(a+2)
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