X square + 6 X + 9 equal to zero
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x^2 +6x + 9 = 0
=> x^2 + 3x +3x + 9 = 0
=> x(x+3) + 3(x+3) = 0
=> (x+3)(x+3) = 0
x = - 3
=> x^2 + 3x +3x + 9 = 0
=> x(x+3) + 3(x+3) = 0
=> (x+3)(x+3) = 0
x = - 3
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x^2 +3x + 3x + 9 =0
x (x+3) + 3 (x + 3) = 0
(x+3) (x+3) = 0
x = -3 ,-3
x (x+3) + 3 (x + 3) = 0
(x+3) (x+3) = 0
x = -3 ,-3
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