Question

x square +6x +5 = 0 I NEED this in berif explanation​

Answer 1

Step-by-step explanation:

x²+6x+5=0

x²+5x+x+5 = 0

x(x+5)+1(x+5)=0

(x+5)(x+1)=0

x=-1,-5

Answer 2

Step-by-step explanation:

${x}^{2} + 6x + 5 = 0 \\ {x}^{2} + 5x + x + 5 = 0 \\ x(x + 5) + 1(x + 5) = 0 \\ (x + 1)(x + 5) = 0 \\ x = - 1 \: or \: x = - 5$

Thank you