Math, asked by farookabdulla, 1 year ago

x square - 8 x - 9 = 0 prove

Answers

Answered by amankumaraman11
0

 {x}^{2}  - 8x - 9 = 0
 =  {x}^{2}  - (9 - 1)x - 9 \\  =  {x}^{2}  - 9x + x - 9 \\  =  x(x - 9) + 1(x - 9) \\  = (x - 9)(x + 1)
x = ( - 1 )\: or \: 9
And, By substituting the values,

 = ( - 1 - 9)( - 1 + 1) =  - 10 \times 0 = 0 \\  \\  = (9 - 9)(9 + 1) = 0 \times 10 = 0

Hence proved.......





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