Question

x square - 8 x - 9 = 0 prove

Answer 1

${x}^{2} - 8x - 9 = 0$
$= {x}^{2} - (9 - 1)x - 9 \\ = {x}^{2} - 9x + x - 9 \\ = x(x - 9) + 1(x - 9) \\ = (x - 9)(x + 1)$
$x = ( - 1 )\: or \: 9$
And, By substituting the values,

$= ( - 1 - 9)( - 1 + 1) = - 10 \times 0 = 0 \\ \\ = (9 - 9)(9 + 1) = 0 \times 10 = 0$

Hence proved.......





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