Question

x square -8x=10using quadratic formula​

Answer 1

completing the square x^2-8x=10. Below is the steps that I have taken:

x^2-8x+16=10+16

x^2-8x =26

(x-4)^2=26

This is where I am completely lost.

Found 2 solutions by fractalier, stanbon:

Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!

From x^2 - 8x = 10, you are right if you have

x^2 - 8x + 16 = 10 + 16

x^2 - 8x + 16 = 26

(x - 4)^2 = 26

Now take the square root of both sides and solve for x, giving you

x - 4 = ± sqrt(26)

x = 4 ± sqrt(26)

and we're done...

Answer by stanbon(75874) (Show Source): You can put this solution on YOUR website!

I am having problems completing the square x^2-8x=10. Below is the steps that I have taken:

x^2-8x=10

x^2-8x+16=10+16

You have to notice now that the left side is a perfect square, so factor it, as follows:

(x-4)^2=26

Now, take the square root of both sides to get:

x-4=+-sqrt26

x=4+sqrt(26 or x=4-sqrt26

Check these solutions in the original equation.

Cheers,

Stan H.

Answer 2

Answer:

$x ^{2} - 8x = 10 \\ \therefore \: x { }^{2} - 8x - 10 = 0 \\ therefore \: a = 1 \: \: \: b = - 8 \\ c = - 10 \\ \\ \\therefore \: by \: using \: formula \\ \\ b { }^{2} - 4ac = ( - 8) {}^{2} - 4(1)( - 10) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 64 + 40 = 104 \\ \\ \: \:$