Question

x square+ax+b is a perfect square
if the 16 is a value of b find a

Answer 1

Answer:

8

Step-by-step explanation:

${x}^{2} + ax + 16 = 0 \\ {x}^{2 } + ax + {4}^{2} = 0 \\ it \: is \: in \: the \: form \: of \: {g {}^{2} + h} ^{2} + 2gh = 0 \\ \\ comparing \: the \: terms \\ \\ g = x \\ h = 4 \\ \\ 2gh = ax \\ \\ so \: a = 2h \: as it \: is \: a \: perfect \: sq. \\ a = 2 \times 4 = 8$