x square is equal to t square + 1 then acceleration is
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Answered by
4
Answer:
X is position here so
X=t^2+1
now double differentiate that is
first of all take out velocity
so velocity=dx/dr
so v=d(t^2+1)/dr
=2t
and acceleration equals to
a=dv/dr
so a=2
hope it helped you
Answered by
0
Answer:
Explanation:
X is position here so
X=t^2+1
now double differentiate that is
first of all take out velocity
so velocity=dx/dr
so v=d(t^2+1)/dr
=2t
and acceleration equals to
a=dv/dr
so a=2
hope it helped you
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