Question

(x) square+k (4x+k+1) +2=0 has equal roots then k =​

Answer 1

Step-by-step explanation:

(x) square+k (4x+k+1) +2=0 has equal roots then

b^2- 4ac=0

we have x^2 +4kx +k^2 +k + 2 =0

a= 1 , b = 4k , c = k^2+k+2

now (4k)^2 - 4( 1 )( k^2+k+2 ) =0

16k^2 -4k^2-4k-8 = 0

12k^2 -4k - 8 =0

3k^2-k - 2 =0

3k^2 -3k + 2k - 2 =0

3k( k -1) + 2 ( k-1 ) =0

(k-1) (3k+2) =0

k = 1 or k= -2/3