x square minus 11 x + 8 by completing square method
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x² - 11x + 8 = 0
x² - 11x = - 8
add both sides, (11/2)²
x² - 11x + (11/2)² = - 8 + (11/2)²
x² -2(11/2).x + (11/2)² = (-32 + 121)/4
( x - 11/2)² = ( 89)/4
take square root both sides ,
(x - 11/2) = ±√189/2
x = 11/2 ± √89/2
hence, ( 11 + √89)/2 and ( 11-√89)/2 are the roots of x² - 11x + 8
x² - 11x = - 8
add both sides, (11/2)²
x² - 11x + (11/2)² = - 8 + (11/2)²
x² -2(11/2).x + (11/2)² = (-32 + 121)/4
( x - 11/2)² = ( 89)/4
take square root both sides ,
(x - 11/2) = ±√189/2
x = 11/2 ± √89/2
hence, ( 11 + √89)/2 and ( 11-√89)/2 are the roots of x² - 11x + 8
Answered by
0
x²-11x+8 = 0
x²-11x = -8
adding (11/2)² on both sides,
x²-11x+(11/2)² = -8+(11/2)²
x²-2(x)(11/2)+(11/2)² = -8+121/4
(x-11/2)² = (-32+121)/4
(x-11/2)² = 89/4
take square root on both sides,
√(x-11/2)² = ±√(89/4)
(x-11/2) = ±√89/2
x = 11/2 ± √89/2
x = (11±√89)/2
therefore,the roots of x²-11x+8 are {(11+√89)/2} and {(11-√89)/2}
hope it helps...…
x²-11x = -8
adding (11/2)² on both sides,
x²-11x+(11/2)² = -8+(11/2)²
x²-2(x)(11/2)+(11/2)² = -8+121/4
(x-11/2)² = (-32+121)/4
(x-11/2)² = 89/4
take square root on both sides,
√(x-11/2)² = ±√(89/4)
(x-11/2) = ±√89/2
x = 11/2 ± √89/2
x = (11±√89)/2
therefore,the roots of x²-11x+8 are {(11+√89)/2} and {(11-√89)/2}
hope it helps...…
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