x square minus 16 whole by x power minus 4
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What is the best way to factor x⁴-16?
The difference of squares: a² - b² factors to (a - b) (a + b)
Let x⁴ = (x²)²
Let 16 = 4²
Now by difference of squares x⁴ - 16 factors as (x² - 4)(x² + 4)
The front factor, (x² - 4), can factor by difference of squares again as (x - 2)(x + 2)
In this way x⁴ - 16 = (x - 2)(x + 2)(x² + 4)
Only if you dip into imaginary numbers can you factor this any farther.
If you use imaginary numbers then (x² + 4) can become (x² -(-4)) and the square root of -4 is 2i
so (x² - (-4)) becomes (x + 2i)(x - 2i). As a result using imaginary numbers, you can factor x⁴ - 16 into even smaller factors
x⁴ - 16 = (x - 2)(x + 2)(x - 2i)(x + 2i)
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