X square minus 2 root 5 x minus 15 is equals to zero
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Answer:root5+2root5
And root5-2root5
Explanation:
Firsty,we have to apply
B^2-4ac
(2root5)^2-4*1*(-15)
4*5+4*15
20+60
80
So the eq^n has real roots
Now,
X=-b+-root b^2-4ac/2a
X= 2root5+-root80/2
If,
X=2root5+root80/2
X=2root5+4root5/2
X=2(root5+2root5)/2
X=root5+2root5
And,
Simuntanesoly,
X=root5-2root5
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