Question

x square minus kx + K - 1 is equal to zero has equal roots​

Answer 1

Answer:

Root of the equation = 1

Step-by-step explanation:

x² - kx + k -1= 0

Let the roots be R and R

ie, x² - kx + k -1 =  (x-R) (x-R)

2R = k and R² = k - 1

ie, R² = 2R - 1

R² - 2R + 1 = 0

Solving this equation,

(R-1) * (R-1) = 0

R = 1

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