Question

x square minus root 3 x plus 1=0

Answer 1

${x}^{2} - \sqrt{3} x + 1 = 0 \\ \\ = > x = \frac{ - ( - \sqrt{3} ) \binom{ + }{ - } \sqrt{3 - 4 \times 1 \times 1} }{2 \times 1} \\ \\ = > x = \frac{ \sqrt{3} \binom{ + }{ - } \sqrt{3 - 4} }{2} \\ \\ = > x = \frac{ \sqrt{3} \binom{ + }{ - } \sqrt{ - 1} }{2} \\ \\ = > x = \frac{ \sqrt{3} \binom{ + }{ - }i }{2} \\ \\ = > x = \frac{ \sqrt{3} + i }{2}, \frac{ \sqrt{3} - i }{2}$