Question

x square minus root 3x minus6​

Answer 1

Step-by-step explanation:

x^2 - √3x -6 = 0, the value of x = -b±√(b^2-4ac)/2a, = √3 ± √( 3-4(1)(-6) )/2 = √3± √(27)/2 = (√3±3√3)/2 = 4√3/2, -2√3/2= 2√3, -√3. Hence the values of x are ( 2√3, -√3) respectively. Hope this helps you

Answer 2

Answer: I hope this helps you