Question

X square minus (start root 3 + 1) close X + root 3 is equal to zero

Answer 1

Answer:

x=\sqrt{3},1x=3,1

Step-by-step explanation:

Given : x^2-(\sqrt{3} +1)x+\sqrt{3} =0x2−(3+1)x+3=0

To find : Solve for x?

Solution :

The given expression is in quadratic form,

x^2-(\sqrt{3} +1)x+\sqrt{3} =0x2−(3+1)x+3=0

Open the bracket,

x^2-\sqrt{3}x -x+\sqrt{3} =0x2−3x−x+3=0

Arrange in order s.t. there is common,

x(x-\sqrt{3}) -1(x-\sqrt{3})=0x(x−3)−1(x−3)=0

(x-\sqrt{3})(x-1)=0(x−3)(x−1)=0

(x-\sqrt{3})=0,(x-1)=0(x−3)=0,(x−1)=0

x=\sqrt{3},x=1x=3,x=1

Therefore, The value of x is x=\sqrt{3},1x=3,1