x square minus three x plus one =0
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x² - 3x + 1 = 0
By Quadratic equation,
a = 1
b = 3
c = 1
Then,
Discrimunant = b² - 4ac
D = 3² - 4(1×1)
D = 9-4
D = 5
Now,
Quadratic equation = [-b±√d]/(2a)
=> [-3±√5]/(2×1)
Roots are :-
• (-3+√5)/2 = x
OR.
• (-3 - √5)/2 =x
I hope this will help you
-by ABHAY
By Quadratic equation,
a = 1
b = 3
c = 1
Then,
Discrimunant = b² - 4ac
D = 3² - 4(1×1)
D = 9-4
D = 5
Now,
Quadratic equation = [-b±√d]/(2a)
=> [-3±√5]/(2×1)
Roots are :-
• (-3+√5)/2 = x
OR.
• (-3 - √5)/2 =x
I hope this will help you
-by ABHAY
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