X square minus under root 3 x minus 6 is equal to zero
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x^2 - √3x -6 = 0, the value of x = -b±√(b^2-4ac)/2a, = √3 ± √( 3-4(1)(-6) )/2 = √3± √(27)/2 = (√3±3√3)/2 = 4√3/2, -2√3/2= 2√3, -√3. Hence the values of x are ( 2√3, -√3) respectively. Hope this helps you
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