X square minus y square is equals to 2 x y then dy by dx
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Q=X^2-Y^2=2xy;
=>(x^2-y^2)/2x=y.
By differentiating wrt x;
=>dy/dx=(2x-2y)2x-2(x^2-y^2).
=>dy/dx=4x^2-4xy-2x^2-2y^2.
=>dy/dx=2x^2-2y^2-4xy//
=>(x^2-y^2)/2x=y.
By differentiating wrt x;
=>dy/dx=(2x-2y)2x-2(x^2-y^2).
=>dy/dx=4x^2-4xy-2x^2-2y^2.
=>dy/dx=2x^2-2y^2-4xy//
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