x square minus Y square = (x+y) x
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Let us solve the problem using multiplication of the two terms (x+y)(x+y) and (x-y)(x−y) ,
\quad (x+y)(x-y)(x+y)(x−y)
=x(x-y)+y(x-y)=x(x−y)+y(x−y)
[ Using distributive property of multiplication over addition ]
=x^{2}-xy+yx-y^{2}=x2−xy+yx−y2
[ Since (+)(+)=(+)(+)(+)=(+) and (+)(-)=(-)(+)(−)=(−) ]
=x^{2}-xy+xy-y^{2}=x2−xy+xy−y2
[ Since multiplication of commutative, that is yx=xyyx=xy ]
=x^{2}-y^{2}=x2−y2
[ Since a-a=0a−a=0 ]
\Rightarrow (x+y)(x-y)=x^{2}-y^{2}⇒(x+y)(x−y)=x2−y2
\Rightarrow \boxed{x^{2}-y^{2}=(x+y)(x-y)}⇒x2−y2=(x+y)(x−y)
Step-by-step explanation:
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