Question

X square plus 3 root 3 x minus 30

Answer 1

Answer:

$\displaystyle x=-5\sqrt3 \ or \ x=2\sqrt3$

Explanation:

Given :

$\displaystyle p(x)=x^2+3\sqrt3x-30$

By splitting mid term we have

$\displaystyle p(x)=x^2+3\sqrt3x-30\\\\\displaystyle p(x)=x^2+5\sqrt3x-2\sqrt3x-30\\\\\displaystyle p(x)=x(x+5\sqrt3)-2\sqrt3(x+5\sqrt3)\\\\\displaystyle p(x)=(x+5\sqrt3)(x-2\sqrt3)$

For zeroes of p ( x )

$\displaystyle p(x)=(x+5\sqrt3)(x-2\sqrt3)=0\\\\\displaystyle (x+5\sqrt3)=0\\\\\displaystyle \text{ x=-5\sqrt3 or }\\\\\displaystyle (x-2\sqrt3)=0\\\\\displaystyle x=2\sqrt3\\\\\displaystyle \text{Thus we get x=-5\sqrt3 \ or \ x=2\sqrt3 }$