Question

x square plus x minus 2 is equal to 0
​

Answer 1

$\tt{ {x}^{2} + x - 2 = 0} \\ \tt{ {x}^{2} + 2x - x - 2 } \\ \tt{x(x + 2) - 1(x + 2)} \\ \tt{(x - 1)(x + 2) = 0} \\ \tt {x = 1 \: or \: x = - 2}$

Answer 2

Answer:

Step-by-step explanation:

x^2+x-2=0

x^2+x-2x-2=0

taking out commons

x(x+1) -2(x+1)=0

(x-2) (x+1)=0

x-2=0

x=2

x+1=0

x=-1

Hence,

zeroes are 2 and -1