Question

X square + root 2 + root 4 is equal to zero find the value of x

Answer 1

$x^{2} + \sqrt{2} + \sqrt{4} = 0$

$\implies x^{2} + \sqrt{2} + \sqrt{2^{2}} = 0$

$\implies x^{2} + \sqrt{2} + 2= 0$

$\implies x^{2} = -(2+\sqrt{2})$

$\implies x = ±\sqrt{-(2+\sqrt{2})}$

Therefore.,

$\red {Value \:of \:x } \green {= ±\sqrt{-(2+\sqrt{2})}}$

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