Math, asked by ps284147, 1 year ago

x + square root of x [ to the power 2] +1= a. then find the value of x . please fast

Answers

Answered by hemanth92

1

x+√x^2+1=a
√x^2+1=a-x
square on both sides
x^2+1=a^2+x^2-2ax
1=a^2-2ax
2ax=a^2-1
x=(a^2-1)/2a

ps284147: please help its very urgent . and i am using my computer so it will take a lot of time to transfer the image from mobile to comp.

ps284147: how we will solve the question if root is for both x square and +1.

hemanth92: sorry i didn't get your point

ps284147: i mean that if here at the place of just x if the root is places on both the digits =root of [x square+1]

hemanth92: now i undertood the problem tomorrow early in the morning will send you the solution don't worry GD night

ps284147: ok . thanks and good night . please try to solve my other question as well. request.

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