X square + X + 1 ka whole square barabar 365
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Answered by
5
(x^2+X+1)^2=365
(x^2)^2+2^2+1^2+2×X^2×x^2+2×x×1+2×1×x^2=365
By this formula u can find it :-
a^2+b^2+c^2+2ab+2bc+2ca
HOOE IT HELPS
IF YES,PLZ MARK AS BRAINLIST
(x^2)^2+2^2+1^2+2×X^2×x^2+2×x×1+2×1×x^2=365
By this formula u can find it :-
a^2+b^2+c^2+2ab+2bc+2ca
HOOE IT HELPS
IF YES,PLZ MARK AS BRAINLIST
Answered by
8
X^2+(x+1)^2=365
X^2+[(X)^2+(1)^2+2*1*x} =365
X^2+(x^2+1+2X)=365
X^2+X^2+1+2x=365
2X^2+2X+1=365
2X^2+2X=365-1
2X=364-2X^2
X=364-2X^2/2x
X=182-2
X=180
Therefor the valve of x is 180
X^2+[(X)^2+(1)^2+2*1*x} =365
X^2+(x^2+1+2X)=365
X^2+X^2+1+2x=365
2X^2+2X+1=365
2X^2+2X=365-1
2X=364-2X^2
X=364-2X^2/2x
X=182-2
X=180
Therefor the valve of x is 180
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