Question

x square - X - 132
solution of this​

Answer 1

Answer:

$\large\boxed{\sf{-11\;and\;12}}$

Step-by-step explanation:

Given a quadratic expression such that,

${x}^{2} - x - 132$

To find its solution.

We need to equate the expression to 0 making ut a quadratic equation.

Therefore, we will get,

$= > {x}^{2} - x - 132 = 0$

Now, to find the solution,

We have to factorise the equation by middle term splitting method.

Therefore, we will get,

$= > {x}^{2} - 12x + 11x - 132 = 0 \\ \\ = > {x}^{2} + 11x - 12x - 132 = 0$

Now, taking the common terms out, we get,

$= > x(x + 11) - 12(x + 11) = 0\\ \\ = > (x + 11)(x - 12) = 0$

Therefore, we have two cases.

Case I

When x + 11 = 0

=> x = -11

Case II

When x - 12 = 0

=> x = 12

Hence, the solutions are -11 and 12.

Answer 2

Question:

x²- x - 132

Solution:

the given expression is x²-x - 132

Firstly , we have to find two numbers whose sun = x and product =132

Clearly , such numbers are - 12 and 11

$\therefore \: \sf {x}^{2} - x - 132 \\ \sf = {x}^{2} - 12x + 11x - 132 \\ \sf \: = x(x - 12) + 11(x - 12) \\ \sf = (x - 12)(x + 11)$

$\bold {the \: formula \: used \: is \: } \bold {\underline {\red{ {ax}^{2} + bx + c}}}$